MULOK

 ASSALAMU ALAIKUM WR.WB.

Hay sobat blogger ku,dimana saya akan membagikan sebuah HTML untuk blog,dimana sebuah cursor memiliki nama yang mengikuti cursor anda:

<style type='text/css'>
/* Circle Text Styles */
#outerCircleText {
font-style: italic;
font-weight: bold;
font-family: 'comic sans ms', verdana, arial;
color: #0000FF;/*Ganti warna sesuai keinginan*/
position: absolute;top: 0;left: 0;z-index: 3000;cursor: default;}
#outerCircleText div {position: relative;}
#outerCircleText div div {position: absolute;top: 0;left: 0;text-align: center;}
</style>
<script type='text/javascript'>//<![CDATA[
/* Circling text trail- Tim Tilton - Website: http://www.tempermedia.com/ - Visit: http://www.dynamicdrive.com/ for Original Source and tons of scripts.
Modified Here for more flexibility and modern browser support
Modifications as first seen in http://www.dynamicdrive.com/forums/
username:jscheuer1 - This notice must remain for legal use
*/
;(function(){
var msg = "MUH.FIRMAN.S"; // Ganti tulisan sesuai keinginan
var size = 24;
var circleY = 0.75; var circleX = 2;
var letter_spacing = 5;
var diameter = 10;
var rotation = 0.4;
var speed = 0.3;
////////////////////// Stop Editing //////////////////////
if (!window.addEventListener && !window.attachEvent || !document.createElement) return;
msg = msg.split('');
var n = msg.length - 1, a = Math.round(size * diameter * 0.208333), currStep = 20,
ymouse = a * circleY + 20, xmouse = a * circleX + 20, y = [], x = [], Y = [], X = [],
o = document.createElement('div'), oi = document.createElement('div'),
b = document.compatMode && document.compatMode != "BackCompat"? document.documentElement : document.body,
mouse = function(e){
e = e || window.event;
ymouse = !isNaN(e.pageY)? e.pageY : e.clientY; // y-position
xmouse = !isNaN(e.pageX)? e.pageX : e.clientX; // x-position
},
makecircle = function(){ // rotation/positioning
if(init.nopy){
o.style.top = (b || document.body).scrollTop + 'px';
o.style.left = (b || document.body).scrollLeft + 'px';
};
currStep -= rotation;
for (var d, i = n; i > -1; --i){ // makes the circle
d = document.getElementById('iemsg' + i).style;
d.top = Math.round(y[i] + a * Math.sin((currStep + i) / letter_spacing) * circleY - 15) + 'px';
d.left = Math.round(x[i] + a * Math.cos((currStep + i) / letter_spacing) * circleX) + 'px';
};
},
drag = function(){ // makes the resistance
y[0] = Y[0] += (ymouse - Y[0]) * speed;
x[0] = X[0] += (xmouse - 20 - X[0]) * speed;
for (var i = n; i > 0; --i){
y[i] = Y[i] += (y[i-1] - Y[i]) * speed;
x[i] = X[i] += (x[i-1] - X[i]) * speed;
};
makecircle();
},
init = function(){ // appends message divs, & sets initial values for positioning arrays
if(!isNaN(window.pageYOffset)){
ymouse += window.pageYOffset;
xmouse += window.pageXOffset;
} else init.nopy = true;
for (var d, i = n; i > -1; --i){
d = document.createElement('div'); d.id = 'iemsg' + i;
d.style.height = d.style.width = a + 'px';
d.appendChild(document.createTextNode(msg[i]));
oi.appendChild(d); y[i] = x[i] = Y[i] = X[i] = 0;
};
o.appendChild(oi); document.body.appendChild(o);
setInterval(drag, 25);
},
ascroll = function(){
ymouse += window.pageYOffset;
xmouse += window.pageXOffset;
window.removeEventListener('scroll', ascroll, false);
};
o.id = 'outerCircleText'; o.style.fontSize = size + 'px';
if (window.addEventListener){
window.addEventListener('load', init, false);
document.addEventListener('mouseover', mouse, false);
document.addEventListener('mousemove', mouse, false);
if (/Apple/.test(navigator.vendor))
window.addEventListener('scroll', ascroll, false);
}
else if (window.attachEvent){
window.attachEvent('onload', init);
document.attachEvent('onmousemove', mouse);
};
})();
//]]></script>

KIMIA

 ASSALAMU ALAIKUM WR,WB.

Kembali lagi di blog firman,kali ini saya akan memposting mapel saya yang kimia:

Penentuan ∆H Dengan Hukum Hess

1.    Dengan menggunakan hukum hess

Hukum hess menyatakan jika suatu proses dapat berlangsung melalui beberapa tahapan maka perubahan entalpi secara keseluruhan adalah sama tidak peduli tahapan mana yang dilalui.

Rumus : ∆H_{1 =} ∆ H₂ + ∆H₃